Question

Which graph represents the solutions to the inequality |2x - 6| <= 10?

Answer 1

@jdoe0001 Hate to bother you again. Last one if you can help

Answer 2

\(\large {|2x - 6| \le 10
\\ \quad \\\implies
\begin{cases}
+(2x-6)\le 10\to 2x-6\le 10\to 2x\le 16\to x\le \frac{\cancel{ 16 }}{\cancel{ 2 }}
\\ \quad \\
-(2x-6){\color{red}{ \le}} 10\to 2x-6{\color{red}{ \ge }}10\to 2x\ge 16\to x\ge \frac{\cancel{ 16 }}{\cancel{ 2 }}
\end{cases} }\)

Answer 3

hmmm forgo to change the 10 to -10

so one sec

Answer 4

no problem:)

Answer 5

\(\large {
|2x - 6| \le 10
\\ \quad \\

\begin{cases}
+(2x-6)\le 10\to 2x-6\le 10\to 2x\le 16\to x\le \frac{\cancel{ 16 }}{\cancel{ 2 }}
\\ \quad \\
-(2x-6){\color{red}{ \le}} 10\to 2x-6{\color{red}{ \ge }}-10\to 2x\ge -4\to x\ge \frac{\cancel{ -4 }}{\cancel{ 2 }}
\end{cases}
}\)

Answer 6

so what i got from those two is

Answer 7

one second..

Answer 8

Im trying to press the draw button but theres an ad blocking it urghh

Answer 9

hehe

Answer 10

first one

Answer 11

second

Answer 12

so im going to say A?

Answer 13

is the yellow the empty part? or the part for "x" that's taking?

Answer 14

yellow? :o

Answer 15

ohhhh

Answer 16

the lines are drawn in the blue :)

Answer 17

ohh hmmm

Answer 18

so... what did you get for "x" anyway?

Answer 19

ermm -2 i believe looking back (i shouldve kept the page i was working on)

Answer 20

eheh

Answer 21

\(\large {
|2x - 6| \le 10
\\ \quad \\

\begin{cases}
+(2x-6)\le 10\to 2x-6\le 10\to 2x\le 16\to x\le \frac{\cancel{ 16 }}{\cancel{ 2 }}
\\ \quad \\
-(2x-6){\color{red}{ \le}} 10\to 2x-6{\color{red}{ \ge }}-10\to 2x\ge -4\to x\ge \frac{\cancel{ -4 }}{\cancel{ 2 }}
\end{cases}\\ \quad \\
\implies
\begin{cases}
x\le 8\\
x\ge -4
\end{cases}\implies -4\le x \le 8
}\)

notice is a \(\Large \le \ and\ \ge\ thus the number are included, thus is a solid circle, not a hollow one

Answer 22

hmmm
notice is a \(\Large \le \ and\ \ge\) thus the number are included, thus is a solid circle, not a hollow one

Answer 23

wooops hmmm I meant to put a -2 there any

Answer 24

hmm so A would be correct

Answer 25

\(\large {
|2x - 6| \le 10
\\ \quad \\

\begin{cases}
+(2x-6)\le 10\to 2x-6\le 10\to 2x\le 16\to x\le \frac{\cancel{ 16 }}{\cancel{ 2 }}
\\ \quad \\
-(2x-6){\color{red}{ \le}} 10\to 2x-6{\color{red}{ \ge }}-10\to 2x\ge -4\to x\ge \frac{\cancel{ -4 }}{\cancel{ 2 }}
\end{cases}
\\ \quad \\

\implies
\begin{cases}
x\le 8\\
x\ge -2
\end{cases}\implies -2\le x \le 8
}\)

Answer 26

if the blue means area taken by "x", yes

Answer 27

alright, thank you bunches for all you're help!

Answer 28

yw