Question

help please urgent
Integral of 2sin(3x) + e^3x - 1dx

Answer 1

https://cims.nyu.edu/~kiryl/Calculus/Section_6.1--Integration_by_Parts/Integration_by_Parts.pdf

Answer 2

By parts? Just separate it.

\[\large \int 2sin(3x) + e^{3x} - 1 dx\]
becomes
\[\large \int 2sin(3x)dx + \int e^{3x}dx - \int 1dx\]

Answer 3

Remember all constants can be moved outside the integral so we have

\[\large 2\int sin(3x)dx + \int e^{3x}dx - 1\int dx\]

Answer 4

And it looks like some simple u-subs will do the trick :)

Answer 5

\[2-\cos(3x)\div3+e^3x/3-1x+c is this correct?\]

Answer 6

\[\large -\frac{2}{3}cos(3x) + \frac{1}{3}e^{3x} - x + c\]

indeed!

Answer 7

excellent thanks so very much xoxo

Answer 8

Anytime :)