Question

Hey I need Help!!

Answer 1

Is it No Solution??

Answer 2

why not? seems solvable to me

Answer 3

start by combining the left hand side in to one log
the rewrite in equivalent exponential form

Answer 4

Well I solved it i got two x's. I got x = 3 and x= -2. I tried to check it but thay didnt come out right

Answer 5

i meant x = -1 and 3

Answer 6

oops i meant
\[x(x-2)=8\]

Answer 7

those are not the two solutions

Answer 8

Oh. Can you help me what the two solutions are

Answer 9

\[\log_2(x(x-2))=3\] is the first step

Answer 10

right

Answer 11

\[x(x-2)=2^3\\
x(x-2)=8\] is the second

Answer 12

\[x^2-2x=8\]is the third, and you can solve this by completing the square or by solving
\[x^2-2x-8=0\] by factoring

Answer 13

\[(x+2)(x-4)=0\\x=-2,x=4\]
4 works, 2 does not

Answer 14

i mean -2 does not

Answer 15

oh ok