Question

f(x)=-(x+1)^2+4 find the zeroes

Answer 1

\[-(x+1)^2+4=0\\
(x+1)^2=4\] would be a good first step

Answer 2

We then do the square root?

Answer 3

yes, don't forget the \(-\) as well

Answer 4

Wait, but isn't 0-4=-4

Answer 5

@satellite73

Answer 6

I know one of the zeroes are going to be one, but what about the other?

Answer 7

hold on lets back up

Answer 8

Okay

Answer 9

\[-(x+1)^2+4=0\]
add \((x+1)^2\) to both sides, that is what gives
\[4=(x+1)^2\]

Answer 10

i just wrote it as
\[(x+1)^2=4\]
if you subtract \(4\) from both sides you get
\[-(x+1)^2=-4\] like you said, but you then change the signs and get
\[(x+1)^2=4\]

Answer 11

Okay

Answer 12

that means
\[x+1=2\] which gives \(x=1\) or
\[x+1=-2\] which gives \(x=-3\)

Answer 13

I see