Question

Flip a coin until heads shows, assume that the probability of heads on one flip is \(\large \frac{3}{5}\). We define a RV (random variable) X = number of flips.

Find the probability that X will be no more than 10.

Answer 1

So I have the geometric series \(\huge \frac{3}{5}*\frac{2}{5}^n\). I assume the numerator of the probability goes from 0 (or 1?) to 10

Answer 2

\[\huge \frac{3}{5}*\frac{2}{5}^n\]

Answer 3

is latex broked

Answer 4

i think it is almost 1
\[\frac{3}{5}\sum_{k=0}^{10}(\frac{2}{5})^k\]

Answer 5

first flip \(.6\)
second flip \(.4\times .6\)
third flip \(.4^2\times .6\)
fourth flip \(.4^3\times .6\) etc
ok make that \[\frac{3}{5}\sum_{k=0}^{9}(\frac{2}{5})^k\] when you add