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find the second derivative of f(x)=cosx+3secx help pls
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would the first drivative be -sinx+3tanxsecx?
you are correct
derive that to get f '' (x) you'll have to use the product rule to derive tan(x)*sec(x)
would the 2nd deri be -cosx+3secx^2secs+3tanxtanxsecx?
correct, you can do a bit of simplification but you have the correct answer more or less
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how do you simplify that?
well you could factor out 3sec(x) from 3secx^2secx+3tanxtanxsecx to get 3sec(x)*[sec^2(x) + tan^2(x)]
so overall, the second derivative is f '' (x) = -cos(x) + 3sec(x)*[sec^2(x) + tan^2(x)]
hmmm ok thanks :D
you're welcome
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