Find the values of m and b that make f differentiable everywhere. f(x)=x^2, if x=2 f(x)= mx+b, if x>2. I know how to do these types of problems with only one variable, but am lost with two.
ok so we do need it to be continuous to be differentiable
so we need the left limit to equal the right limit as we approach x=2
\[\lim_{x \rightarrow 2^-}f(x)=\lim_{x \rightarrow 2^+}f(x) \\ \lim_{x \rightarrow 2^-}x^2=\lim_{x \rightarrow 2^+}(mx+b) \\ \]
evaluate the limit on both sides
and since you want it to also need the function to be smooth in order to be differentiable then you need the left derivative to equal the right derivative
\[\lim_{x \rightarrow 2^-}f'(x)=\lim_{x \rightarrow 2^+}f'(x) \\ \lim_{x \rightarrow 2^-}2x=\lim_{x \rightarrow 2^+}m\]
aha. so we will have a system of equations
you therefore have a system of equations to solve
lol yeah
thanks a lot
do you think you need further assistance with this one
nah i got it thanks man
I probably need assistance in slowing down my typing so my sentences will actually make sense
or woman lol
nah i prefer not waiting forever
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i understand them at least haha
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am i sure?
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like a truck with mudflaps
Maybe it is to deceive you
yeah thats why i added that haha. But you never know nowadays
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