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f(x)=|x+3|. Find all solutions to f(x-1)=x+4
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\[f(x)=|x+3|,f(x-1)=?\]
the question on the homework is as stated. Where f(x-1)=x+4. I'm not sure where to start
is it |x+3|-1=x+4 ?
bno
it is \[f(x-1)+|x-1+3|=|x+2|\]
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\[f(\color{red}{x}) = |\color{red}{x}+3|\]So \(f(\color{red}{x-1})= |\color{red}{x-1}+3|=\underline{\underline{\underline{|x+2|}}}\)
\underline\underline\underline i like it
oh... so where does the x+4 come in?
oh.. |x+2|=x+4 solve x
Yeah, so you "split" it into two cases, one where x+2 is positive and another one where x+2 is negative, so you have two equation to solve: \(x+2 = x+4\\x+2=-(x+4)\) Does that make sense?
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click. thank you. makes sense.
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