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Mathematics 8 Online
OpenStudy (anonymous):

The no. of violent crimes committed in a day is a positively skewed distribution with a mean of 41. crimes per day and standard deviation of 6 crimes per day. A random sample of 100 days was observed, and the sample mean of crimes calculated. The sampling distribution of the sample mean is approximately positively skewed with a mean of 4.1 and sd 0f 0.60? true or false

OpenStudy (anonymous):

the mean is 4.1 not 41

OpenStudy (queelius):

The standard error of the sampling distribution is expected to be: \[\frac{ \sigma }{ \sqrt{n} }\] And the sample mean y-bar is expected to be u, that is, E[y-bar] = u. That is to say, both the standard error and y-bar are unbiased estimators. (Technically, the square root of the sample variance is not an unbiased estimator of the standard deviation of the population, but this is generally ignored.)

OpenStudy (queelius):

So, n = 100, therefore sqrt(n) = 10. Thus, if the standard deviation of the population is 4.1, then the standard deviation (standard error) of the sampling distribution of sample means is 4.1 / 10.

OpenStudy (queelius):

Errr, not 4.1 / 10, but 6 / 10.

OpenStudy (kropot72):

The distribution of the sample means will be approximately Normal. With reference to the Central Limit Theorem, the large number of samples (100) will give this result.

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