Question

Liquid A has 1rams of element X per liter. Liquid B has 1 milligrams of element Y per cm^3 (there are 10milligrams in a gram and 10 cm^3 in a liter). It is desired to make 1grams of molecule Z.

Answer 1

@perl

Answer 2

ok

Answer 3

damn, draw button doesnt work

Answer 4

can you tag me again, brb

Answer 5

im back

Answer 6

.2

Answer 7

oh wait, we want 120 grams of z

Answer 8

oh right right

Answer 9

ok

Answer 10

i can see that

Answer 11

an easier way:
2/18 is the fractional amount of X in Z ,
and 16/18 is the fraction of the amount of Y in Z. this is true always. (if you multiply by 18, you get 2 and 16 respectively)

now if you have 120 grams, this fractional amount wont change
120 * 2/18 = grams of X in Z
120 * 16/18 = grams of Y in Z

Answer 12

120 * 2/18 = 13.333... grams of X
120 * 16/18 = 106.666... grams of Y

Answer 13

ok now we can go back and use our conversion factor to find how many liters of liquid A and B we need

Answer 14

alright