let ABC be a triangle with perimeter P and area A. now R is any point in the triangle or on the boundary of triangle. There is a point S in the plane of figure (that is the point can be inside as well as outside the triangle) such that RS<=5 . now find area enclosed by the region by LOCUS OF point S.
|dw:1413994095399:dw|
my locus
how to calculate area of those arcs at 3 corners?
@AnswerMyQuestions ? @HelpBlahBlahBlah ?
till now iam getting 5P+A+(area of 3 circular arcs)
@phi ? @Zarkon ?
@radar ?
the 3 "corners" will have angles = angle of the triangle's angle all will have radius 5 the sum of the 3 angles = 180 the curved parts will add up to 1/2 of the area of a circle with r= 5
from that we will get 12.5 pie
but ans is 25 pie
Let me tweak that to this |dw:1413995040904:dw|
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