let ABC be a triangle with perimeter P and area A. now R is any point in the triangle or on the boundary of triangle. There is a point S in the plane of figure (that is the point can be inside as well as outside the triangle) such that RS<=5 . now find area enclosed by the region by LOCUS OF point S.
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OpenStudy (anonymous):
|dw:1413994095399:dw|
OpenStudy (anonymous):
my locus
OpenStudy (anonymous):
how to calculate area of those arcs at 3 corners?
OpenStudy (anonymous):
@AnswerMyQuestions ? @HelpBlahBlahBlah ?
OpenStudy (anonymous):
till now iam getting 5P+A+(area of 3 circular arcs)
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OpenStudy (anonymous):
@phi ? @Zarkon ?
OpenStudy (anonymous):
@radar ?
OpenStudy (phi):
the 3 "corners" will have angles = angle of the triangle's angle
all will have radius 5
the sum of the 3 angles = 180
the curved parts will add up to 1/2 of the area of a circle with r= 5
OpenStudy (anonymous):
from that we will get 12.5 pie
OpenStudy (anonymous):
but ans is 25 pie
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