Question

Implicit differentiation help

Answer 1

the original equation was: \[find \frac{ dy }{ dx }: \frac{ \cos(x^2y^2) }{ \sin(x^2y^2)}=2x\]

I simplified it to\[\cot(x^2y^2)=2\]
I did a chain rule and product rule to get: \[-\csc^2(x^2y^2)(2x^2yy'+2y^2x)=2\]

I'm not sure if I did all this right but I don't know where to go from here

Answer 2

You mean this (when you say you simplified it to):
\[(\cot(x^2y^2))'=2\]
But anyways
distribute the -csc^2(x^2y^2) as a first step

Answer 3

After you use the distribute property.
Put all your terms that y' on one side and all your terms that don't have y' on the opposite side