Question

Find the term in x^k for the indicated value of k in the expansion of (x+x^2)^3 k=2

Answer 1

\[(x+x^2)^3\] find the term in \[x^2\]

Answer 2

When i calculated using the the General term, I got does not exist since i got r=-1

Answer 3

\[GT=13Cr(6x)^{13-r}(x^2)^{r}\]

Answer 4

My bad that should be 3 no 13

Answer 5

oh woops im reading the wrong answer for the question lol

Answer 6

I would factor out the x which will become x^3 outside.
Will there ever be an x^2 term?

Answer 7

(x+x^2)^3 = {x(1+x)}^3 = x^3 * (1+x)^3

Answer 8

\[GT=3Cr(x)^{3-r}(x^2)^r\]
\[=3Cr(x)^{3+r}\]<--when simiplified

Answer 9

using the exponents law i did 3+r=2 and got r=-1 the term DNE, can someone confirm that?

Answer 10

Read my reply above.

Answer 11

right so it does not exist right

Answer 12

x^3 * (1+x)^3
The lowest exponent after expansion will be 3. There will be no x^2 term. It does not exist.

Answer 13

alright thanks

Answer 14

yw.