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Mathematics 12 Online
OpenStudy (anonymous):

Suppose that f(x) is a function with f(105)=25 and f '(105)=4. Estimate f(106). Not sure how to go about this problem..

OpenStudy (freckles):

\[y-f(a)=f'(a)(x-a) \\ y=f'(a)(x-a)+f(a) \]

OpenStudy (freckles):

\[f(x) \approx f'(a)(x-a)+f(a) \text{ for values of x near a }\]

OpenStudy (freckles):

Hello? Do you know what the above is? The first line is point slope form of the tangent line of f at (a,f(a)) The second line is the same equation I just added f(a) on both sides. I'm using it as a linear approximation for numbers x near a

OpenStudy (anonymous):

hello! I'm sorry for the late reply, my computer crashed due to a failed update yesterday. But yes I understand this now, thank you so much for your help!

OpenStudy (freckles):

np

OpenStudy (freckles):

so you know your a is 105 in this case?

OpenStudy (freckles):

\[f(x) \approx f'(105)(x-105)+f(105) \text{ for values of x near a }\]

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