Question

Can someone show me how to finish this problem?

Answer 1

2. Simplify the rational expression and state any excluded values:
\[\frac{ x }{ x^2 + 2x - 24 } \div \frac{ 2 }{ x^2 + 4x - 12}\]

Answer 2

I've gotten to:
\[\frac{ x }{ (x - 4) (x + 6) } \times \frac{ (x - 2)(x + 6) }{ 2 }\]

Answer 3

The (x + 6)'s cross out.

Answer 4

Which brings you to: \[\frac{ x }{ (x - 4) } \times \frac{ (x - 2) }{ 2 }\]

Answer 5

Would it be:
\[\frac{ x^2 - 2x }{ 2x - 8 }\]
? Do the 2x's cross out?

Answer 6

good job
you have one thing common on the numerator
and one thing on the denominator

Answer 7

i know you should find that let me know what is that

Answer 8

Oh! I see, so it should be:
\[\frac{ x(x - 2) }{ 2(x - 4) }\]
?

Answer 9

yep right

Answer 10

good job !!!!!!!!!!!!!!!!!!!! :)

Answer 11

Thanks! So the excluded values are 4, and -6, right?

Answer 12

and 2