Question

please help me with this: (
linear differential equations)
ydx-4(x+y^6)dy=0

Answer 1

is the differential equation exact?

Answer 2

I have to do it for the method of linear differential equations

Answer 3

well what does that exactly mean...
Have you not talked about exact differential equations?

Answer 4

no, that is a diferent method,
linear differential equations: dy/dx+p(x)y=f(x)

Answer 5

so can you put it in that form then?

Answer 6

I don't think you can but if you can I will help you further.

Answer 7

\[y-4(x+y^6)y'=0 \\ -4(x+y^6)y'+y=0 \\ y'+\frac{-1}{4(x+y^6)}y=0\]
see how that isn't in that form?

Answer 8

\[y'+p(x,y)y=f(x)\]

Answer 9

it sould be just P(X) not P(X,Y)

Answer 10

well then can you show me how you get p(x) there then

Answer 11

because I don't see how

Answer 12

that is the problem that I have haha

Answer 13

You can't put the problem in y'+p(x)y=f(x) form

Answer 14

the thing next to the y is p(x,y) not p(x)

Answer 15

there has to be some other way you have learned besides putting it in that form and basing the integrating factor off that form

Answer 16

also you called this a linear diff equation
it is a nonlinear