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The equation of the curve whose slope at point (x,y) is x^2-2 and which contains the point (-1,3) is...
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@amistre64
@zepdrix
@thomaster
what is our 'antiderivative'? or just integrate
1/3x^3-2x
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+C we need to determine C that satisfies the initial condition
oh yeah
so y = 1/3 x^3 - 2x + C, when x=-1, y=3 what should C be?
-4/3?
maybe :) 3 = -1/3 +2 + C 1 = -1/3 + C i dont think its -4/3
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x is actually 1, y is actually -3 I typed it wrong sorry
pfft, then your on your own :)
y=1/3x^3-2x-4/3, thanks for the help :)
yep ;)
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