Question

HELP with CHAIN RULE!!!!!!

y= e^(x^2 +1) * sinx^3

Answer 1

looks like you need the product rule

Answer 2

yes but you wud first use chain rule wouldn't you?

Answer 3

\[\left(fg\right)'=f'g+g'f\] with
\[f(x)=e^{2x+1},f'(x)=2e^{2x+1},g(x)=\sin(x^3), g'(x)=3x^2\cos(x^3)\]

Answer 4

yeah you do need the chain rule to find the derivative of \(e^{2x+}\) and \(\sin(x^3)\)

Answer 5

oh wow i never thought of it that way! So now use product rule?

Answer 6

except why wud f(x) be 2x? it wud be x^2 right?

Answer 7

like it would be e to the power of x^2 +1 not 2x +1

Answer 8

@satellite73

Answer 9

consider the chain rule as:\[y(x)=f(u)\]
\[\frac{dy}{dx}\frac{dx}{dx}=\frac{df}{du}\frac{du}{dx}\frac{dx}{dx}\]

Answer 10

for example:

\[y = e^{x^2 +1} \]
\[\frac{dy}{dx} = \frac{d(e^{x^2+1})}{d(x^2+1)}\frac{d(x^2+1)}{dx}\]
if we let u = x^2+1
\[\frac{dy}{dx} = \frac{d(e^{u})}{du}\frac{du}{dx}\]

Answer 11

y' = 2x e^u