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xy+x=12, dx/dt=-3, x=2, y=5 find dy/dt
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\[y+xy'+1=0\] put \[x=2,y=5\] solve for \(y'\)
\[y \frac{ dx }{ dt }+x \frac{ dy }{ dt }+\frac{ dx }{ dt }=0\]
and plug everything in (:
ohhh waitt i think that's wrong
Nevermind, it's correct
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what is dy/dt?
by implicit differentiation and the chain rule
\[(xy \prime+yx \prime)+x \prime=0\]
\[y \prime \] is dy/dt and\[x \prime \] is dx/dt
thanks so much ill would the answer be -3? or -9? those are two i have came up with
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It should be 9, not -9
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