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Mathematics 21 Online
OpenStudy (anonymous):

Help with finding the height of a cone! In the following diagram, the central angle is measured in radians. Express the height (h) of the cone in terms of theta and R. I know that r = R * theta / 2*pi. Am I right in saying h = 3V / (R^2 * theta / 2) ? Thanks!

OpenStudy (anonymous):

OpenStudy (anonymous):

\[r = R \theta / 2\] \[Area of sector: R^2\theta / 2\] \[h = 3V / (R^2\theta / 2)\]

OpenStudy (anonymous):

Would that be correct?

OpenStudy (aum):

Oops, forgot to square 'r' earlier and so deleting that reply. \[ R\theta = 2\pi r \\ r = \frac{R\theta}{2\pi} \\ L = R \\ h^2 + r^2 = L^2 \\ h^2 = L^2 - r^2 = R^2 - \left(\frac{R\theta}{2\pi}\right)^2 = R^2\left(1 - \frac{\theta^2}{4\pi^2}\right) = R^2\left(\frac{4\pi^2 - \theta^2}{4\pi^2}\right) \\ h = \frac{R}{2\pi}\sqrt{4\pi^2 - \theta^2} \]

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