Question

2^x=4^y=8^z and xyz =288 then the value of1/2 x+1/4y+1/8z is

Answer 1

2^x=2^2y=2^3z xyz=288

Answer 2

2^(x+2y+3z)

Answer 3

@waterineyes

Answer 4

\((2)^x = (2)^x\)
\((4)^y = (2)^{2y}\)
\((8)^z = (2)^{3z}\)

Answer 5

\[(x)^a = (x)^b \implies a = b\]

Answer 6

Meaning : \(x = 2y = 3z\)

Answer 7

x = 2y
x = 3z
xyz = 288

Answer 8

Still having problem anywhere?

Answer 9

x*x/2*x/3=288 ,x^3=1728

Answer 10

x=12

Answer 11

so 1/24+1/96+1/288 =16/288 =1/18

Answer 12

Got??

Answer 13

Wait.. Have you done it correctly?

Answer 14

nope.i think so

Answer 15

\(x=12\), is right.. :)

Answer 16

\[\frac{1}{2x} + \frac{1}{4y} + \frac{1}{8z} \implies \frac{1}{24} + \frac{1}{2(2y)} + \frac{1}{8 \frac{x}{3}}\]

Answer 17

\(2y = x\), so \(2(x) = 24\)

Answer 18

\(4y = 2(2y) = 2(x) = 24\)

\[\frac{x}{3} = 4\]

Answer 19

So, in denominators, all will be \(24\) right?

Answer 20

yes

Answer 21

\[\frac{1}{24} + \frac{1}{24} + \frac{1}{24} = ??\]

Answer 22

3/24=1/8

Answer 23

for x=3z 8z=?

Answer 24

@waterineyes

Answer 25

\[x = 3z \implies z = \frac{x}{3}\]

Answer 26

Getting?

Answer 27

Now multiplying by \(8\) both the sides.. :)

Answer 28

\[8z = 8 \times \frac{x}{3} = 8 \times \frac{\cancel{12}^4}{\cancel{3}} = 32\]

Answer 29

Sorry, but you should understand that I am not God, I am man only.. :P

Answer 30

lol:)

Answer 31

\[\frac{1}{24} + \frac{1}{24} + \frac{1}{32} \]

Answer 32

rofl::)

Answer 33

Sorry, rofl?

Answer 34

How much you got?

Answer 35

11/96 is the right answer.:)

Answer 36

x= 12 , y = 24, z= 36

1/(2*12 ) + 1 / ( 4 *24 ) + 1 / ( 8 * 36 ) = 1/18

Answer 37

nope @perl.

Answer 38

\[\frac{11}{96}\]

I also got the same.. :)

Answer 39

another two problems

Answer 40

\[x = 12 = 2y \not \implies y = 24\]

Answer 41

*does not imply..

Yeah sure, go ahead.. :)

Answer 42

can i close the question or put here

Answer 43

It is totally up to you.. :)

Answer 44

simple one makes me time so .over here
x+1/x=5 then x^6+1/x^6=?

Answer 45

x+(1/x)=5 then x^6+(1/x^6)=?

Answer 46

Okay wait.. :)

Answer 47

Do you know the formula for : \((a+b)^3\)

Answer 48

yes

Answer 49

a^3+b^3+3ab(a+b) .here i used it but it gave 3 as answer

Answer 50

Let us go step by step, with the basic formula we have.. :)

Answer 51

x^2+1/x^2=23

Answer 52

\[(a+b)^2 = a^2 + b^2 + 2ab \implies \color{green}{a^2 + b^2 = (a+b)^2 - 2ab}\]

Answer 53

Oh, you have used that?? Good.. :)

Answer 54

\(x^2 + \frac{1}{x^2} = 25 - 2 = 23\)

Answer 55

(x^2+1/x^2)^3

Answer 56

23^3=12167

Answer 57

\[(a+b)^3 = a^3 + b^3 + 3ab(a+b) \implies x^6 + \frac{1}{x^6} = (23)^3 - 3(23)\]

Answer 58

12098

Answer 59

\[\implies 23(23^2 - 3) = 23(529 - 3) = 23 \times 526 = ?\]

Answer 60

\(12098\)

Answer 61

Good.. Is that the right answer or not?

Answer 62

another formulae also there to find see. (5)(a+b)^2

Answer 63

Which formula?

Answer 64

same
(a+b)^3=(a+b)(a+b)^2

Answer 65

Yes.. :)

Answer 66

maybe I misread the question

Answer 67

It is okay.. :)

Answer 68

what was the correct answer ?

Answer 69

And what is the \(\text{Third}\) question?

Answer 70

5(23)^2-2 something wrong

Answer 71

11/96 is correct @perl

Answer 72

how do you get that? x = 12 , correct?

Answer 73

I think you cannot use that formula here.. :)

Answer 74

, x = 12, y = 24, z = 36

Answer 75

x = 12 is correct.. :)

Answer 76

'o' is the centre of the circle,AB is the chord of the circle OM perpendicular to AB.If AB=20cm and OM=2sqrt(11)cm,then the radius of the circle is,

Answer 77

how did you get 11/ 96, i must be reading the formula incorrectly

Answer 78

2y = x not 2x = y @perl

Answer 79

you are finding y and z incorrectly.. :)

Answer 80

ok

Answer 81

y =6 and z = 3 then

Answer 82

This looks good.. :)

Answer 83

@harish1 while using that formula do mention what are a and b there.. :)