Question

Hey guys! I just need help finishing a problem!
y=e^x(secx)

So far I have u= e^x. u'=e^x, v=secx, v'=secxtanx
So I set it up as (e^x)(secxtanx)+(e^x)(secx)

Need help simplifying!

Answer 1

are you trying to find the derivative of y ?

Answer 2

ohhh sorry yes!

Answer 3

looks you have applied the product rule correctly

Answer 4

you're done with calc part

Answer 5

Right! I just don't know how to simplify this :/

Answer 6

you can take \(e^x \cdot \sec(x)\) common for that.. :)

Answer 7

*from, not for.. :)

Answer 8

But this will not be called as Simplifying it, it will be just rearrangement only.. :P

Answer 9

so I guess I'm just wondering what the final product be?

Answer 10

putting the final answer in a nice format is good, but is ur prof particular about niceness ?

Answer 11

I think we can just rearrange it only,,

Answer 12

if you're just asked to find the derivative, you're done right after applying the product rule

Answer 13

Ohhh okay. On my test, he said I was okay until that point. I tried to simplify it farther and he marked points off. So maybe that's what he meant!? To just stop after the product rule?

Answer 14

lol he should not cut marks just because you made it look better

Answer 15

anyways he is correct in someways, this is calc course, focus should be on learning calc concepts...

Answer 16

Haha true true. While I got you here, do you mind checking to see if I took this other problem as long as I could, as well?

Answer 17

sure, ask wil try..

Answer 18

y=tanx/x

u=tanx
u'=sec^2(x)
v=x
v'=1

So I put it all together and got
(x) (sec^2(x) - (1) (tanx) / x^2

Answer 19

looks good, but nobody leaves (1)(tanx) like that :o

Answer 20

oh. right

Answer 21

soooo (x)(sec^2(x)) - (tanx) / x^2

Answer 22

It can't be simplified any further right?

Answer 23

(xsec^2x - tanx) / x^2


looks good as final answer

Answer 24

note that parenthesis should be there for the entire numerator

Answer 25

Gotcha! Great!!! Thank you so much! :)

Answer 26

np :)