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Physics 18 Online
OpenStudy (zephyr141):

Center of Mass and External Forces.

OpenStudy (zephyr141):

i got two blocks at set distances of x1 and x2. their masses are m1 and m2 as well. |dw:1414073919270:dw|

OpenStudy (zephyr141):

find the x-coordinate of of the center of mass of the system. i found that to be \[\frac{ m_{1}x_{1}+m_{2}x_{2} }{ m_{1}+m_{2} }\]this looks correct?

OpenStudy (zephyr141):

i'm having trouble with this one; Recall that the blocks can only move along the x-axis. the x-components of their velocities at a certain moment ar v(1x) and v(2x). find the x-component of the velocity of the center of mass v(cm)x at that moment. keep in mind that , in general: \[v_{x}=\frac{dx}{dt}\]express your answer in terms of \[m_{1},m_{2},v_{1x},v_{2x}\]

OpenStudy (anonymous):

Take the derivative of the center of mass equation

OpenStudy (zephyr141):

hmm.. ok. let me try to remember derivatives.

OpenStudy (zephyr141):

so derivative of \[\frac{ m_1x_1+m_2x_2 }{ m_1+m_2 }\] where does the t come from? i'm reeeeeaaally rusty on derivatives...

OpenStudy (anonymous):

v = dx/dt

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