medal! check my answers please c:
what answers
1. Solve the system by substitution- 2x+y=-11, 3x-4y=11. a.(3,5) b.(-5,-3) c.(-3,-5)*** d.(5,3) 2. Solve the system using elimination- 2x+6y=-12, 5x-5y=10. a.(2,1) b.(0,-2)*** c.(-2,0) d.(1,2) 3.What is the solution of the following system?-3x-2y=-12, 9x+6y=-9.
3.What is the solution of the following system?-3x-2y=-12, 9x+6y=-9. a.(2,1)*** b.no solution c.(-2,-1) d.infinitely many solutions
@II-Heartless-ll sorry took me a min to type everything out s:
its cool
ok so looking at the first one. basically you have to multiply one or both of the equations by a number so that the coefficient of one of the variables is the same so that when you subtract/add them then it will cancel. ^that sounds confusing, here's an ex for elimination: x+y=5, 2x+y = 30 so if we multiplied the first equation by 2, we'd get: 2x+2y=10 right? so we can subtract now... 2x+2y=10 - 2x+y=30 ------------ 0 + y = -20 ------------- and now we can plug in -20 for y back in the equation to find x.
you there
got to go :]
sorry! I was getting ready to pick up my little sis from school x: i'm here so my answer for #1 is correct?
@emma97
@Happpily
@sammixboo
@trevorttreesh
check my answers please ? :c
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