Question

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Answer 1

I think j is the unit vector that lays on the y-axis right?
is that [0,1,0] ?

Answer 2

\[[1,-3,-2]+[4,-5,3]-[5(0),5(1),5(0)]\]

Answer 3

well first perform those operations above

Answer 4

\[[1+4-5(0),-3+(-5)-5(1),-2+3-5(0)]\]

Answer 5

We are just combining the x components, the y's , and the z'

Answer 6

then | | means we will find the magintude of that resulting vector

Answer 7

\[\sqrt{(1+4-5(0))^2+(-3+(-5)-5(1))^2+(-2+3-5(0))^2}\]

Answer 8

are you still there?

Answer 9

you said j was the unit vector that lays on the y-axis

Answer 10

so -5j=-5(0,1,0)=(0,-5,0)

Answer 11

u+v-5j
=(1,-3,-2)
+(4,-5,3)
+(0,-5,0)
---------
( , , )

Answer 12

\[|(a,b,c,)|=\sqrt{a^2+b^2+c^2}\]