what is the equation of the line slope 5 and y-intercept-2?
y = 5x - 2
do you understand or do you want me to explain this?
please explain my choices are a. 5x+y=2 b. 2x-y=5 c. 5x-y=2 d. 2x+y-5
so they want it in standard form
it would be C
y = 5x - 2 x needs to be in the beginning so cancel out y 5x - y = 2
Standard form Ax - By = C
So, when you do this, you need to change the sign of 5x because its going over the equal sign. Corret? so over all once you get, y=mx+-B you just subtract y.
yes
and this cause -2 to become 2
The equal sign always needs to go at the end? Or is this just because of the answer choices
always, it's just like a two-step equation
Can I ask you to do another question? Explaining it step by step?
Which is an equation of the line with slope -2/3 passing through the point (-10,0)?
ok so that equation would start like y = mx + b
m is your slope. You know your slope is -2/3 so plug that in
Yes, I just have trouble with the B
b = 0 so just put nothing, (-10,0) the y - intercept = 0
So, the Y in your coordinate is always B?
yes b = y-intercept
Ok, what would be the answer? If i plug it in, it's not one of my answer choices
what are the answer choices
A. Y= -2/3x -10 B. 2x+3y = 10 C. Y= +10 = -2x D. Y= -2/3x - 20/3
B
Ok, so the numerator is always x?
No, here wait let me explain more
in standard form x always has to be positive and it has to be rational. So -2/3x + y = 10 is unacceptable you must cancel out the fraction by doing 3/1 times -2/3, canceling out the 3 and leaving the 2 behind What you do to x you must do to y So y times 3 is 3y
Leaving it 2x + 3y = 10
-2/3x + y =10?
yes, standard form is Ax + By = C Our first equation was y = -2/3x x must be in the beginning to move the -2/3x to the front and add + y
I'm only in 8th grade, I have no idea what this all means, I understand the Standard Form, but "x must be in the beginning to move the -2/3x to the front and add + y" I have no clue on.
So you understand Standard Form, you know which ever number (rational or irrational) that has the variable "x" must be in the beginning
Standard form = No Fractions or Mixed number's, Correct?
Yes, and which ever number holds the variable "x" it MUST be positive
So "x" must be rational and positive
"y" doesn't have too
So, Y= -2/3, would be 2x+3y = 0? Because 0 is the Y Intercept
no the constant is on the other side of the equal sign, not the y - intercept
Constant? -1 - (-100) and 1-100? All even and positive number's? That probably something stupid to know, its just tomorrow I have a test on this but without the answer choices.
to ask, not to know
a constant is any number that does not hold a variable
2x is not a constant but -46 is
Only negatives?
so 10 in our case is our constant
no
just any number without a variable
Oh, I remeber now. So it's Ax + By = C, x MUST be positive, so its 2x + 3y = -10, the 3y comes from the denominator, correct?
2x + 3y = 10, its positive during the switch You get 3y because you multiplied -2/3 by 3, and you must do the same to the "y". Remember, the "y" was by itself and didn't have any number attached, but 3 times y makes it 3y
So if it's -3/7 it would be, 3x +7y = 10?
Yes, you understand it's because you multiplied 7 right?
It's very simple when "y" is by itself, but most of the time "y" won't be by itself
Try doing 5/8x + 2y = 10 by yourself
I'm here if you need help
So like, when Y not going to be by itself? Or would this be above 8th grade? (Algebra 1)
I'm in 8th grade Algebra 1 and 9/10 times y is not by itself
idk if your teacher is different but it's better if you understand also when y is not by itself
you will be better prepared for the EOC (or whatever test you take in your state. I lie in Florida and we take the EOC)
live in Florida**
EOG, End of Grade So, 9/10y? or 9/10*y
I'm going to try one, Slope: -6, (-2,4) would y= -6x + 4 be Correct?
yes
If you don't understand anything else search "Khan Academy" on google, they have GREAT videos that go in great detail in basically everything that makes up Algebra 1
I myself must use the website sometimes
I have to go now, but if I were you I would really consider staying up a little later or waking up earlier tomorrow and looking up "Khan Academy" to study for your test
Thank you, :)
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