Question

What are the zero(s) of the function f(x) =

Answer 1

\[\frac{ 4x^2-36x }{ x-9 }\]
@IMStuck

Answer 2

x = -9

x = 0

x = 9

x = 0 and x = 9

Answer 3

x = 9 is wrong, thought it was that one but got it wrong

Answer 4

Make x=0 what would you answer be?

Answer 5

would it be 0?

Answer 6

If I were you, I would use long division of polynomials and find the zeros that way. LIke this:

Answer 7

4(0)^2 = 0 36(x) = 0
0 - 9 = -9

0 / -9 = 0?

This chapter is confusing to me

Answer 8

Yes, it is 0 when x is 0. Because the numerator is 0 and 0 over anything is always 0. Plus if you factor the numerator, you get 4x(x-9) and that x-9 cancels out with the denominator leaving you with just 4x. 4x=0 when x = 0

Answer 9

Thanks, I got a 100%! :)