Ask your own question, for FREE!
Mathematics 13 Online
OpenStudy (anonymous):

http://gyazo.com/f6cd34893dc845eca0d0a61500763ce5

OpenStudy (anonymous):

whats up

OpenStudy (anonymous):

Figure: http://gyazo.com/0d4c71d84519b7b772dbae3a050d737e

OpenStudy (triciaal):

next time post the question first

OpenStudy (anonymous):

The question IS posted there @triciaal

OpenStudy (love10129151):

is this goemetry

OpenStudy (anonymous):

Yep

OpenStudy (anonymous):

sorry cant help you with this one i have not learned it yet

OpenStudy (anonymous):

Ah man, this is due tonight. Anyone else that can maybe help :p ?

ganeshie8 (ganeshie8):

hint : \[\large \text{inscribed angle} = \dfrac{\text{arc measure}}{2}\]

ganeshie8 (ganeshie8):

find the angles ADE and BAD first

OpenStudy (triciaal):

all paraphraased the angle at center is directly proportional to the length of the arc

OpenStudy (anonymous):

So @ganeshie8 it would be either A or B right?

ganeshie8 (ganeshie8):

Im not sure which question are we working on

ganeshie8 (ganeshie8):

I see you have attached two links and they have different questions

ganeshie8 (ganeshie8):

could you clarify

OpenStudy (triciaal):

if the center = O the angle ACE = 1/2 AOE

OpenStudy (anonymous):

oh the second like is just the measure (ignore the text on top of it). The original screenshot is the one I'm working on. With the A, B, C and D options. @ganeshie8

OpenStudy (anonymous):

@triciaal Their is no option for ACE = 1/2(AOE)

ganeshie8 (ganeshie8):

still i dont get it, could you put everything in one picture and post it ?

OpenStudy (anonymous):

Yea sorry one second

OpenStudy (anonymous):

This is the problem: http://gyazo.com/f6cd34893dc845eca0d0a61500763ce5

OpenStudy (anonymous):

Where it says "in the diagram above". This is the Diagram it is talking about: http://gyazo.com/5c19372ed3b430ce2387dab9775da392

OpenStudy (triciaal):

@CoolGuy13 I was just working through "aloud" I don't have the actual answer yet and I can't see your options. I am not very fast with these either. just trying to help. as expressed by @ganeshie8 as well given the arc length find the angles. you have 45 and 110

OpenStudy (anonymous):

@triciaal Thanks for helping!

OpenStudy (anonymous):

@ganeshie8 Do you see the new problem?

ganeshie8 (ganeshie8):

Alright, so you're working on Part II, question a ?

OpenStudy (anonymous):

Yes

ganeshie8 (ganeshie8):

Okay good, there is a formula for finding the angle ACE outside a point : \[\large m\angle ACE = \dfrac{\text{far arc - near arc}}{2}\]

ganeshie8 (ganeshie8):

look at the given diagram from angle ACE

ganeshie8 (ganeshie8):

far arc = ? near arc = ?

OpenStudy (anonymous):

far arc = AE near arc = BD

ganeshie8 (ganeshie8):

perfect ! so plug them in

ganeshie8 (ganeshie8):

\[\large m\angle ACE = \dfrac{\text{mAE - mBD}}{2} \]

OpenStudy (anonymous):

So answer would be B ?

ganeshie8 (ganeshie8):

Yep!

OpenStudy (anonymous):

32.5 for part B?

OpenStudy (anonymous):

AE = 110 BD = 45 110 - 45 = 65 65 / 2 = 32.5 m<ACE = 32.5

OpenStudy (anonymous):

And for Part C, how would i use this to find M<BAD ? @ganeshie8

ganeshie8 (ganeshie8):

m<ACE = 32.5 is \(\large \color{Red}{\checkmark}\)

ganeshie8 (ganeshie8):

use inscribed angle formula for part C

ganeshie8 (ganeshie8):

\[\large \text{inscribed angle} = \dfrac{\text{arc measure}}{2}\]

OpenStudy (anonymous):

What would arc measure be?

ganeshie8 (ganeshie8):

BAD eats the arc 45 right ?

OpenStudy (anonymous):

Yea

OpenStudy (anonymous):

45 / 2 ?

ganeshie8 (ganeshie8):

Yep!

OpenStudy (anonymous):

thank you so much @ganeshie8. I have 2 (a lot shorter) more problems and this is due in about an hour. Think you can help me out with them?

ganeshie8 (ganeshie8):

sure post them here

OpenStudy (anonymous):

5: Part 1 & 2: http://gyazo.com/2a7ec73723131211c1e628a4d81e4c30

OpenStudy (anonymous):

Would part 1 be 360 - 90 ?

OpenStudy (anonymous):

@ganeshie8 ?

ganeshie8 (ganeshie8):

Part I : \[\large \dfrac{90}{360}\]

ganeshie8 (ganeshie8):

which equals 1/4 right ?

ganeshie8 (ganeshie8):

basically the length of arc AB would be 1/4 of the circumference of the full circle

ganeshie8 (ganeshie8):

knw how to work part II ?

OpenStudy (anonymous):

emmm

OpenStudy (anonymous):

Can you refresh my memory?

ganeshie8 (ganeshie8):

diameter = 32 radius = ?

ganeshie8 (ganeshie8):

circumference = \(\large 2~\pi ~r = ?\)

OpenStudy (anonymous):

Wait isn't the equation right on top of the figure?

OpenStudy (anonymous):

http://gyazo.com/744b6067a2b5fe4cb89dcbeb981122cc

ganeshie8 (ganeshie8):

yes

ganeshie8 (ganeshie8):

you have already calculated mAB/360 = 90/360 = 1/4

ganeshie8 (ganeshie8):

find the circumference and multiply that by 1/4

OpenStudy (anonymous):

2 * 3.14 * 16 = 100.48 * 1/4 = 25.12

OpenStudy (anonymous):

Is that right?

ganeshie8 (ganeshie8):

looks good!

OpenStudy (anonymous):

Ok phew one last question left, i really appreciate all the help man (:. http://gyazo.com/5328a5976af86524e1292cc261061266

OpenStudy (anonymous):

If that's ok with you

ganeshie8 (ganeshie8):

diameter = 20 radius = ?

OpenStudy (anonymous):

radius = 10

ganeshie8 (ganeshie8):

|dw:1414131147632:dw|

ganeshie8 (ganeshie8):

Full circle = 360 if you cut it into 20 pieces like above, what would be the angle at center ?

ganeshie8 (ganeshie8):

|dw:1414131241869:dw|

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!