Convergence, divergence
Determine if each series is a convergent series or a divergent series. |dw:1414130559264:dw|
Would you use a root test, ratio test or integral test for this?
I was trying ratio test
but my cat took my ink pen
i got it back
Haha, Hi freckles
under what circumstance would you use an integral test
i would never use integral test if I had a factorial or alternating series
it would have to be something I could at least integrate
true XD makes sense
root test also doesn't sound right either
because of the factorial business
i have you tried ratio test
crap seriously she keeps taking my pen
\[\lim_{n \rightarrow \infty}| \frac{(n+1)!}{(n+1)^{n+1}} \frac{n^n}{n!}|\]
I'm working on it right now
how would you simplify the n^n/(n+1)^n+1 part
this is the way i'm approaching it so far \[\lim_{n \rightarrow \infty}| \frac{(n+1)!}{(n+1)^{n+1}} \frac{n^n}{n!}| \\ = \lim_{n \rightarrow \infty}|\frac{n+1}{(n+1)^{n}(n+1)} n^n| \\ =\lim_{n \rightarrow \infty}|(\frac{n}{n+1})^n|\] \[=\lim_{n \rightarrow \infty}|e^{\ln((\frac{n}{n+1})^n)}|=\lim_{n \rightarrow \infty}|e^{n \ln(\frac{n}{n+1})}| \\ = \lim_{n \rightarrow \infty} | e^{\frac{\ln(\frac{n}{n+1})}{\frac{1}{n}}}| \]
for line 2 how did you move the ^n+1
\[x^{2}=x^{1+1}=x^1 x^1\\x^{n+1}=x^{n}x^{1}\]
law of exponents
\[x^rx^s=x^{r+s}\]
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