Question

please help!!!!
Question in attached file.
Moment question.... ._.
Explain pls.... ._.

Answer 1

What do you need help with ?

In your answer to part one you have written Tcos(alpha), I think you mean Fcos(alpha).

Answer 2

Are you told that C is two thirds of the way along the rod ?

Answer 3

Umm the answers i have written are from the answer sheet, not me lol
And It says that AC is two thirds AB

Answer 4

It's really confusing , all of it ;-;

Answer 5

And i am sorry you're absolutely correct, I meant Fcosa

Answer 6

The rod is in equilibrium so that means that if you choose any direction, and add up the components of all the forces along that direction, they have to add up to zero.

Also, if you choose a point and take the moments of all the forces about that point, again they have to add up to zero.

They are the conditions for equilibrium.

Answer 7

True, yes ^^

Answer 8

In your question, you are asked to consider first the components of the forces in the horizontal direction.

Answer 9

The horizontal component of F is Fcos(alpha)

Answer 10

The vertical component of F (for part ii) is Fsin(alpha)

Answer 11

Similarly for the force T

Answer 12

The weight only has a vertical component equal to W because it points vertically down

Answer 13

ie no horizontal component of the weight W

Answer 14

In the third part, moments of the forces are being taken about the end of the rod where the hinge is.

Answer 15

The moment of the force T about the point P is Tdsin(beta), for example

Answer 16

Thank you so muchhhhhh !!!!!!!!!! ^^