Calculus :Find the number of unit x that produces a maxima revenue R. R=228x^2 - 0.08x^3 x= ? units
Are you taking Calculus?
yes
OK, for Calculus questions, I suggest you mark your questions as Calculus and you get a better response from the experts. I should let them answer Calculus questions, but I believe all you need to do it the following. Take the first derivative of your equation. You will get a quadratic equation which you can solve for x using the quadratic equation formula. This will get you x values for the maximum and minimum values that you are seeking. Plug the x value back into your original equation to find the y value or R value in your case. Also, I suggest you use the equation editor by immediately replying to your question and clicking on the equation button.
You can also ping one of the experts. Unfortunately, I don't know how to do it.
Thank you ill edit my question so people know its calculus.
Hello?
Do you still need help?
hi can you help me with this problem?
I agree with marchall in taking the first derivative. Have you done that?
Have you learned power rule? Or are you just allowed to use the definition of derivative to find the derivative?
i got \[456x-0.24x^2\]
Now you want to find the critical numbers.
i learned how to find it by using the second derivative test and finding critical numbers
That means we need find when that is zero.
You can factor your expression.
There is common factor x in both terms.
i g0t 1900=x
and x=0
Those critical numbers look great.
Now as you suggested we can determine if those numbers will give us a max or a min.
By finding second derivative.
second derivative is 456-0.48x
\[f''(x)=456-0.48x \\ f''(0)=456>0 \\ f''(1900)=-456<0\]
So when f'' >0 we have what? and when f''<0 we have?
I like to go back to a real basic graph to help me remember. f(x)=x^2 has a min and f''>0 and if f(x)=-x^2 then f has a max and f''<0
f''>0 min, f''<0 max
yes exactly
Thank you so much ! this really helped a lot!
You did all the work jackie. I think you know more than you think you do.
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