Question

I have to find the concentration of HCl from the results of a potentiometric acid-base titration.

The result of the equivivalent point is:

V = 19 mL (0,1 M NaOH/ mL)
pH = 7

and the HCl used: 10 mL of 0,1 M HCl

Anybody who can help?

Answer 1

moles of Acid = moles of base at Equiva. pt.
0.019L * 0.1 M Acid = # moles of Acid