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OpenStudy (anonymous):
MAYDAY!! Question: Calculate pH of the two acids by the equivivalent point, and compare with the diagram. So for HCl (with the concentration of 0,0910 mol/L) I used formula: -logCs = -log0,0910 = 1,040 And this is the answer i dont understand. Out from the diagram i can read the pH as 7 for the equivivalent point, which is no by near close to 1,04. Anybody who can help? THANKS!
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