Question

Please help for a medal?

Answer 1

Simplify cube root of 7 over fifth root of 7.

Answer 2

\[\frac{ \sqrt[3]{7} }{ \sqrt[5]{7} }\]
like this?

Answer 3

Yes, sorry for the delay.

Answer 4

\[7^{1/3}-7^{1/5}\] =
\[7^{2/15}\]
or \[\sqrt[15]{49}\]

Answer 5

not quite...

\[\frac{ \sqrt[3]{7} }{ \sqrt[5]{7} }=\frac{ 7^{\frac{ 1 }{ 3 }} }{ 7^{\frac{ 1 }{ 5 }} }=7^{\left( \frac{ 1 }{ 3 }-\frac{ 1 }{ 5 } \right)}=7^{\left( \frac{ 5 }{ 15 }-\frac{ 3 }{ 15 } \right)}=7^{\frac{ 2 }{ 15 }}=\sqrt[15]{7^2}=\sqrt[15]{49}\]