Question

simplify: sin(sec^-1 x+1/3) I have the answer, just not sure how to get there.

Answer 1

you just asked a similar question earlier didn't you?
it the same process

Answer 2

what is secant though

Answer 3

first is that \(\large \rm sin(sec^{-1}(x)+1/3)\)

Answer 4

secx is just 1/cosx

Answer 5

is what i wrote correct?

Answer 6

yes the answer is square root x^2 + 2x -8 all over x+1 but where did the polynomial come from

Answer 7

I'm asking did you write your problem like this \(\large \rm sin(sec^{-1}(x+1/3))\) or \(\large \rm sin(sec^{-1}(x)+1/3)\) i'm less concerned about the answer they give you
make sure you wrote the right thing.Also, make sure you looking for the right question

Answer 8

I meant it like the first way sorry about that

Answer 9

okay first set \(\large \rm sec^{-1}(x+1/3)=\theta\)
so \(\large \rm sin\theta=x+1/3\)

Answer 10

let's draw a picture that goes with this information

Answer 11

im sorry should be sec(theta)=x+1/3 not sin

Answer 12

we need to find the missing side

Answer 13

ops sorry, forgot what i did! the first one you said was the right expression i was working on the second one lol

Answer 14

let's rebuild!
\(\large \rm sec^{-1}(x)=\theta ~~\Longrightarrow sec\theta=x\)

Answer 15

I will need to ask you to recheck your problem again!
and rewrite the exact expression alright!
use the drawing tool