A = {integers divisible by 2} and B = {integers}, what is A ∩ B?

{...−3, −2, −1, 0, 1, 2, 3 ...}
{ }
{0}
{... −6, −4, −2, 0, 2, 4, 6 ...}

Question

A = {integers divisible by 2} and B = {integers}, what is A ∩ B?
 	
	{...−3, −2, −1, 0, 1, 2, 3 ...}
	{ }
	{0}
	{... −6, −4, −2, 0, 2, 4, 6 ...}

anonymous · Answer

A= 2,4,6,8,10 and etc. Right?

ganeshie8 · Answer

$\large A \cap  B$  is the set with elements common to both  sets$\large A$ and $\large B$

ganeshie8 · Answer

also include negative numbers and 0 :

A  = {...,-10,-8,-6,-4,-2,0, 2,4,6,8,10,...}

anonymous · Answer

Ohhh ok

ganeshie8 · Answer

B is all integers :

B = {...,-10,-9,-8,-7,-6,-5,-4,-3,-2,-1,0,1,2,3,4,5,6,7,8,9,10,...}

ganeshie8 · Answer

what elements are common to both the sets ?

ganeshie8 · Answer

in other words what elements exist in both set A and set B ?

anonymous · Answer

-10,-8,-6,-4,0,2,4,6,8,10

ganeshie8 · Answer

Perfect ! but you need to include ALL even integers since both the given sets have infinite elements

ganeshie8 · Answer

$$\large  A\cap B =   \{\text{all even integers}\}$$

anonymous · Answer

OK so my answer would be?

anonymous · Answer

The last one?

ganeshie8 · Answer

look at the options,
which option has all even integers ?

ganeshie8 · Answer

Yup!

ganeshie8 · Answer

... in the end means the list continues forever to infinity

ganeshie8 · Answer

... in the start means the list continues forever to -infinity to left

ganeshie8 · Answer

so last option represents ALL the even integers

anonymous · Answer

Thaanks