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At what rate is the diagonal of a cube increasing if its edges are increasing at a rate of 2 cm/s?
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the diagonal of a cube = \[d = \sqrt{3x^2}=\sqrt{3}x\] so the length of the diagonal of a cube is proportional to the lenght of the side and therefore they will change at the same rate
i got dz/dt = 2√3
2* radical 3
oh sorry, yes of course it wil be \(\sqrt{3} \times\) times the rate the edges change You're right
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