Mathematics
20 Online
OpenStudy (anonymous):
Simplify this. Contains factorials not too sure...
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OpenStudy (anonymous):
\[\frac{ 4.16\times n! }{ (n+1)!}\]
OpenStudy (anonymous):
\[\frac{ 4.16 \times n ! }{ (n+1)! } = \frac{ 4.16 \times (1 \times 2 \times 3 \times .... (n-1) \times n) }{(1 \times 2 \times 3 \times .... (n-1) \times n \times (n+1)) } = \frac{ 4.16 }{ n+1 }\]
OpenStudy (anonymous):
Where exactly do the 1 x 2 x 3.... come from?
OpenStudy (anonymous):
do you know what is 5!?
OpenStudy (anonymous):
Yes.
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OpenStudy (anonymous):
so please show me 5!
OpenStudy (anonymous):
5x4x3x2x1
OpenStudy (anonymous):
that's right!
OpenStudy (anonymous):
5x4x3x2x1 = 5 x (5 - 1) x (5 - 2) x .... x (5 - 4)
OpenStudy (anonymous):
Yes I know that
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OpenStudy (anonymous):
it looks like
5! = 5 x (5 - 1) x (5 - 2) x .... x 1
n! = n x (n - 1) x (n - 2) x .... x 1
OpenStudy (anonymous):
or
1 x 2 ..... (n - 2) x (n - 1) x n = n!
OpenStudy (anonymous):
how about (n +1)! ???
OpenStudy (anonymous):
for example
5! = (4+1) x 4 x (4 - 1) x (4 - 2) x ...... 1
OpenStudy (anonymous):
The 1 x 2... part just confuses me
(n+1)! = (n+1)(n)(n-1)(n-2)...
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OpenStudy (anonymous):
that should be
(n+1)! = (n+1)(n)(n-1)(n-2)... 3 x 2 x 1
OpenStudy (anonymous):
assume n = 6
OpenStudy (anonymous):
6! = 6 x 5 x 4 x 3 x 2 x 1
OpenStudy (anonymous):
So n + 1 = 7 if n = 6
OpenStudy (anonymous):
7! = 7 x 6 x 5 x 4 x 3 x 2 x 1
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OpenStudy (anonymous):
oh ok I get it now. Thanks so much for your help!!!
OpenStudy (anonymous):
or
(6 + 1)! = (6 + 1) x 6 x (6-1) x (6 - 2) x ....... 3 x 2 x 1
OpenStudy (anonymous):
it is always ended by 3 x 2 x 1
OpenStudy (anonymous):
you are welcome :)