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Mathematics 20 Online
OpenStudy (anonymous):

Simplify this. Contains factorials not too sure...

OpenStudy (anonymous):

\[\frac{ 4.16\times n! }{ (n+1)!}\]

OpenStudy (anonymous):

\[\frac{ 4.16 \times n ! }{ (n+1)! } = \frac{ 4.16 \times (1 \times 2 \times 3 \times .... (n-1) \times n) }{(1 \times 2 \times 3 \times .... (n-1) \times n \times (n+1)) } = \frac{ 4.16 }{ n+1 }\]

OpenStudy (anonymous):

Where exactly do the 1 x 2 x 3.... come from?

OpenStudy (anonymous):

do you know what is 5!?

OpenStudy (anonymous):

Yes.

OpenStudy (anonymous):

so please show me 5!

OpenStudy (anonymous):

5x4x3x2x1

OpenStudy (anonymous):

that's right!

OpenStudy (anonymous):

5x4x3x2x1 = 5 x (5 - 1) x (5 - 2) x .... x (5 - 4)

OpenStudy (anonymous):

Yes I know that

OpenStudy (anonymous):

it looks like 5! = 5 x (5 - 1) x (5 - 2) x .... x 1 n! = n x (n - 1) x (n - 2) x .... x 1

OpenStudy (anonymous):

or 1 x 2 ..... (n - 2) x (n - 1) x n = n!

OpenStudy (anonymous):

how about (n +1)! ???

OpenStudy (anonymous):

for example 5! = (4+1) x 4 x (4 - 1) x (4 - 2) x ...... 1

OpenStudy (anonymous):

The 1 x 2... part just confuses me (n+1)! = (n+1)(n)(n-1)(n-2)...

OpenStudy (anonymous):

that should be (n+1)! = (n+1)(n)(n-1)(n-2)... 3 x 2 x 1

OpenStudy (anonymous):

assume n = 6

OpenStudy (anonymous):

6! = 6 x 5 x 4 x 3 x 2 x 1

OpenStudy (anonymous):

So n + 1 = 7 if n = 6

OpenStudy (anonymous):

7! = 7 x 6 x 5 x 4 x 3 x 2 x 1

OpenStudy (anonymous):

oh ok I get it now. Thanks so much for your help!!!

OpenStudy (anonymous):

or (6 + 1)! = (6 + 1) x 6 x (6-1) x (6 - 2) x ....... 3 x 2 x 1

OpenStudy (anonymous):

it is always ended by 3 x 2 x 1

OpenStudy (anonymous):

you are welcome :)

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