Solve 8^(x−5)=6 for x.
Take some kind of log of each side,\[\Large\rm \ln\left[8^{(x-5)}\right]=\ln(6)\]Do you remember your log rules? :)
\[\Large\rm \log(a^{\color{orangered}{b}})=\color{orangered}{b}\log(a)\]This one in particular.
It allows you to get the "x stuff" out of the exponent position,\[\Large\rm \ln\left[8^{\color{orangered}{(x-5)}}\right]=\ln(6)\]\[\Large\rm \color{orangered}{(x-5)} \ln[8]=\ln(6)\]
Shouldn't be too bad from there :O yah? What do you think?
lol i got up to this part and got stuck
so you get x-5 = (ln6)/(ln8) right?
@zepdrix what should you do next?
Add......... 5? 0_o
\[\Large\rm x=\frac{\ln6}{\ln8}+5\] Yah? :o Weird place to get stuck :D lol
omg i didn't even notice that
lol thank you!!
np c: If you're looking for a numerical value, you would have to rely on your calculator from this point on.
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