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zepdrix (zepdrix):
Take some kind of log of each side,\[\Large\rm \ln\left[8^{(x-5)}\right]=\ln(6)\]Do you remember your log rules? :)
zepdrix (zepdrix):
\[\Large\rm \log(a^{\color{orangered}{b}})=\color{orangered}{b}\log(a)\]This one in particular.
zepdrix (zepdrix):
It allows you to get the "x stuff" out of the exponent position,\[\Large\rm \ln\left[8^{\color{orangered}{(x-5)}}\right]=\ln(6)\]\[\Large\rm \color{orangered}{(x-5)} \ln[8]=\ln(6)\]
zepdrix (zepdrix):
Shouldn't be too bad from there :O yah?
What do you think?
OpenStudy (anonymous):
lol i got up to this part and got stuck
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OpenStudy (anonymous):
so you get x-5 = (ln6)/(ln8) right?
OpenStudy (anonymous):
@zepdrix what should you do next?
zepdrix (zepdrix):
Add......... 5? 0_o
zepdrix (zepdrix):
\[\Large\rm x=\frac{\ln6}{\ln8}+5\]
Yah? :o
Weird place to get stuck :D lol
OpenStudy (anonymous):
omg i didn't even notice that
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OpenStudy (anonymous):
lol thank you!!
zepdrix (zepdrix):
np c:
If you're looking for a numerical value, you would have to rely on your calculator from this point on.