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Chemistry 17 Online
OpenStudy (anonymous):

Which of the below is NOT a voltaic cell? a) Mg/Ag b) Mg/Cu c) Mg/Zn d) Zn/Pb

OpenStudy (anonymous):

I KNOW THAT A AND B IS WRONG

OpenStudy (cuanchi):

you have to check the reduction potentials table and see if the reaction is above or below. Or the difference of the voltage, if it is positive the reaction is sponntaneous

OpenStudy (anonymous):

BOTH OF C AND D ARE BELOW

OpenStudy (cuanchi):

the others?

OpenStudy (anonymous):

OTHERS ARE COMMON EXAMPLE OF THE CELL

OpenStudy (anonymous):

do you mean i have to calculate E if its "positive ">> is included as voltaic cell

OpenStudy (cuanchi):

usually just looking at the relative position of the reactions in the table and knowing that the first element in the couple is the one in the anodo and is going into oxidation, if it is below in the table than the second element you have a spontaneous reaction

OpenStudy (anonymous):

???? but both of two element are below which means ??

OpenStudy (cuanchi):

looks that all of them are voltaic cells

OpenStudy (anonymous):

wow

OpenStudy (anonymous):

there is no correct choice

OpenStudy (anonymous):

?

OpenStudy (anonymous):

this is confusing

OpenStudy (cuanchi):

where is the question from?

OpenStudy (anonymous):

lap experiment voltaic cell

OpenStudy (anonymous):

are you sure

OpenStudy (anonymous):

??

OpenStudy (cuanchi):

I am double checking

OpenStudy (anonymous):

thank you <3

OpenStudy (cuanchi):

The question if from a printed book or typed by the teacher? there is the possibility of a typo mistake in the question?

OpenStudy (anonymous):

i think by a lab instructor

OpenStudy (anonymous):

from these

OpenStudy (anonymous):

this question is pre-lab equation

OpenStudy (anonymous):

sorry *question

OpenStudy (anonymous):

this is the question

OpenStudy (anonymous):

OpenStudy (anonymous):

so it either c or d

OpenStudy (cuanchi):

I dont know!! sorry, you should ask your teacher and let me know the answer so I can learn something. So far we are doing everything fine, the first metal is the one undergoing oxidation and if the reaction is bellow in the table means that the oxidation potential will be higher than the reactions above in the table

OpenStudy (anonymous):

thank you .. i will ,, you did your best though .. much appreciated <3... i will send you the answer later :P

OpenStudy (cuanchi):

Thanks!

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