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Mathematics 15 Online
OpenStudy (anonymous):

help with this question

OpenStudy (anonymous):

OpenStudy (nincompoop):

concave up and down refers to the 2nd derivative of a function

OpenStudy (anonymous):

And is shown always with some curvature I believe.

OpenStudy (anonymous):

so how can i figure out the interval from this graph?

OpenStudy (nincompoop):

first, you need to know the point of inflection

OpenStudy (nincompoop):

without the "curve" you can still identify the point of inflection indirectly but in just the case of concativity, you just need to know when graph of y = f (x) is concave upward on those intervals where y = f "(x) > 0 y = f (x) is concave downward on those intervals where y = f "(x) < 0 If the graph of y = f (x) has a point of inflection then y = f "(x) = 0

OpenStudy (nincompoop):

you can always reverse the process to figure out the original family of function in question

OpenStudy (anonymous):

so for this one it is x<2?

OpenStudy (nincompoop):

why less than 2?

OpenStudy (anonymous):

oh no no its x>2

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