Question

Explain how to solve this fraction problem

Answer 1

\[\frac{ 7 }{ 8 } - \left( \frac{ 4 }{ 5 } + 1\frac{ 3 }{ 4 } \right)\]

Answer 2

it looks a bit messy.
But the first step is change 1 and 3/4 from a mixed number to an improper fraction

Answer 3

7/4

Answer 4

@phi

Answer 5

yeap thus \(\bf \cfrac{ 7 }{ 8 } - \left( \cfrac{ 4 }{ 5 } + 1\cfrac{ 3 }{ 4 } \right) \implies \cfrac{ 7 }{ 8 } - \left( \cfrac{ 4 }{ 5 } + \cfrac{ 7 }{ 4 } \right)\implies \cfrac{ 7 }{ 8 } -\cfrac{ 4 }{ 5 } + \cfrac{ 7 }{ 4 }=\cfrac{\qquad }{{\color{brown}{ lcd?}}}\)

Answer 6

what do you think the LCD would be? or GCF for that matter

a number thas has 8, 5 and 4 as factors..... which one would that be?

Answer 7

well.... actually the parentheses... .should remain.... since it has an operation... so \(\bf \cfrac{ 7 }{ 8 } - \left( \cfrac{ 4 }{ 5 } + 1\cfrac{ 3 }{ 4 } \right) \implies \cfrac{ 7 }{ 8 } - \left( \cfrac{ 4 }{ 5 } + \cfrac{ 7 }{ 4 } \right)=\cfrac{\qquad }{{\color{brown}{ lcd?}}}\)

Answer 8

\[\frac{ 7 }{ 8 } - \left( \frac{ 4 }{ 5 } + 1\frac{ 3 }{ 4 } \right)=n\]
\[\frac{ 7 }{ 8 } - \left( \frac{ 4 }{ 5 } + 1+\frac{ 3 }{ 4 } \right)=n\]
start multiply thru by the largest denominator
\[\frac{ 7(8) }{ 8 } - \left( \frac{ 4(8) }{ 5 } + 1(8)+\frac{ 3(8) }{ 4 } \right)=n\]
\[7- \left( \frac{ 4(8) }{ 5 } + 1(8)+ 3(2) \right)=8n\]
and then the next biggest denominator
\[7(5)- \left( \frac{ 4(8)(5) }{ 5 } + 1(8)(5)+ 3(2)(5) \right)=8(5)n\]
\[7(5)- \left(4(8) + 1(8)(5)+ 3(2)(5) \right)=8(5)n\]
solve for n