Question

Thanx everyone!

Answer 1

You may determine oxidation numbers from a set of rules usually provided for you. In this problem we need two in particular.
The oxidation state of an atom in its elemental form is 0. So Cl_2 and I_2 are elemental forms.
The oxidation state of a monoatomic ion is the same as its charge. This applies to Na (+1), I (-1), and so on.

Answer 2

Once you know the oxidation states, you may determine oxidation and reduction by observing the transfer of electrons. A reduction is a gain in electrons (becomes more negative). An oxidation is a loss in electrons (becomes more positive). The mnemonic device, OIL RIG, is a nice way to remember it; [O]xidation [I]s [L]oss [R]eduction [I]s [G]ain.

The oxidizing agent will be the chemical that is reduced and does the oxidizing. The reducing agent, the one that is oxidized and does the reducing..

Answer 3

Chlorine and iodine are zero... becuz they r pure elements nd aren't bonded .. thus their redox number is zero...
Sodium is 2, iodine in NaI is -2,sodium in NaCl is 2 nd Cl is -2...
Chlorine is being reduced in the reaction while iodine is being oxidized....