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Mathematics 7 Online
OpenStudy (anonymous):

help with a limit problem ? Lol

OpenStudy (anonymous):

@ganeshie8

OpenStudy (anonymous):

\[\lim_{x \rightarrow \infty} x^3/e^x/2\]

OpenStudy (anonymous):

x^3 / e^(x/2)

OpenStudy (anonymous):

sorry its supposed to look like the 2nd one

ganeshie8 (ganeshie8):

take L'hospital 3 times

ganeshie8 (ganeshie8):

numerator reduces to a constant however nothing much happens in the denominator

OpenStudy (anonymous):

so then the constant would be 6/e^x/2 / 8 ?

ganeshie8 (ganeshie8):

\[\large \lim\limits_{x\to\infty} \dfrac{x^3}{e^{x/2}} ~\stackrel{\text{LH 3 times}}{\leadsto\leadsto\leadsto} ~ \lim\limits_{x\to\infty} \dfrac{c}{e^{x/2}} = 0 \]

ganeshie8 (ganeshie8):

exponential function overtakes ANY polynomial

OpenStudy (anonymous):

what ?

ganeshie8 (ganeshie8):

you're right, you get : 6/e^x/2 / 8 which is same as 48/e^(x/2)

ganeshie8 (ganeshie8):

next take the limit

OpenStudy (anonymous):

okay would it be 48/infinity ? lol

OpenStudy (anonymous):

so a constant over infinity equals 0 ????

OpenStudy (anonymous):

why did you leave @ganeshie8 still have unanswered questions :(

OpenStudy (accessdenied):

Yep, a constant divided by an increasingly large number tends towards 0.

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