help with a limit problem ? Lol
@ganeshie8
\[\lim_{x \rightarrow \infty} x^3/e^x/2\]
x^3 / e^(x/2)
sorry its supposed to look like the 2nd one
take L'hospital 3 times
numerator reduces to a constant however nothing much happens in the denominator
so then the constant would be 6/e^x/2 / 8 ?
\[\large \lim\limits_{x\to\infty} \dfrac{x^3}{e^{x/2}} ~\stackrel{\text{LH 3 times}}{\leadsto\leadsto\leadsto} ~ \lim\limits_{x\to\infty} \dfrac{c}{e^{x/2}} = 0 \]
exponential function overtakes ANY polynomial
what ?
you're right, you get : 6/e^x/2 / 8 which is same as 48/e^(x/2)
next take the limit
okay would it be 48/infinity ? lol
so a constant over infinity equals 0 ????
why did you leave @ganeshie8 still have unanswered questions :(
Yep, a constant divided by an increasingly large number tends towards 0.
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