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OpenStudy (anonymous):
how many molecules are there in 124 gram of iron III nitrate
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OpenStudy (zale101):
You divide 124 grams by the molar mass of iron III nitrate(Fe(NO3)3) to get the moles of Fe(NO3)3. Now use the mols you calculated to multiply by avagodro's number 6.022x10^23 to find how many molecules are there.
OpenStudy (zale101):
Avogadro's number is the amound or number of units are there in one mole of substances.
OpenStudy (zale101):
it's always written in 6.022x10^23
OpenStudy (anonymous):
oh okay thank you so much!!!!
OpenStudy (zale101):
No problem :)
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