Question

The resulting temperature when 1kg of ice at 0 degrees Celcius is mixed with 9kg of water at 50 degress Celcius is ----------------------- to the nearest whole number.The specific capacity of water is 4200J/kg/K,the specific latent heat of fusion of ice is 330 000J/kg

Answer 1

q gain = q lost

q = (mass)(change in temp)(specific heat)

Let the final temperature of the water be x
and imagine that there is sufficient energy to melt all the ice so that x > 0

The ice requires 330000 J to melt
plus 4200 * x to raise the temperature to

This energy comes from cooling the remainder of the water
9 * (50 -x ) * 4200

so

330000 + 4200 * x = 9 * ( 50 -x ) * 4200


solve for x



helpful links


here
https://answers.yahoo.com/question/index?qid=20120209161337AAv1YcS

and here

http://www.chemteam.info/Thermochem/MixingWater.html