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Use the formal definition of limit to verify the indicated limit.
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I understand the steps up to the red line.
0<x-2<d |x+5||x-2|<E this is as far as I can get.
|x+5|<8 I think
thats because we are assuming |x-2| < 1 so x < 3
ok
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\(\large |x^2+3x-10|=|x+5|\cdot |x-2| \lt 8 \cdot \delta \) yes ?
yeah because |x+5|<8
yes and in the start, we have \(\delta = \min(\epsilon/8, ~1)\)
yeah, but why does he pic that?
since putting \(\large \delta =1\) makes the value of \(\epsilon/8 \) greater than 1, the value of \(\large \delta \) must be \(\large \epsilon/8\) here
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factoring |f(x) - L| must have given him that hint
are you able to say: \[|x+5||x-2|<\epsilon \] \[|x+5|<8\] \[|x-2|<\epsilon /8\]
that looks good to me!
Ok :) thnx again
np :)
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