what is equivalent to: (3+5(radical3) / (4-2(radical3) *please show steps*
You would have to rationalize the denominator
ok, continue?
\[\frac{ 3+5\sqrt{3} }{ 4-2\sqrt{3}}\] So you would multiply the numerator and the denominator by conjugate of \[4 - 2\sqrt{3}\]
Do you know how to find the conjugate?
yes i think can you explain more please
so the conjugate would be \[4+2\sqrt{3}\] multiply both sides by that and you get \[\frac{ (3+5\sqrt{3})(4+2\sqrt{3}) }{ (4-2\sqrt{3})(4+2\sqrt{3}) }\] Do you think you could simplify that more?
i think so?
so it would be: \[\frac{ 12+6\sqrt{3}+20\sqrt{3}+10\sqrt{9} }{ 16+8\sqrt{3}-8\sqrt{3}-4\sqrt{9} }\] right?
yeah. Can you simplify the radicals/cancel anything out?
then it would be: \[\frac{ 12+26\sqrt{3}+30 }{ 4 }\] right?
yeah, you need to add 12 and 30 too.
so it would be: \[\frac{ 42+26\sqrt{3} }{ 4 }\]
Yeah, you've got it!
is there a way to simplify it more?
divide the top and bottom by 2
can you divide \[26\sqrt{2}\] by 2
yes, its just\[13\sqrt{3}\]
so would it be: \[\frac{ 21+13\sqrt{3} }{ 2 }\]
and that's it?
Yes
ok thank you!
No Problem :)
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