whats the largest rational number less than \(\large \sqrt{2}\) ?
hahaha very funny
(there isn't one)
why, in the previous page it said rational numbers are ordered so imm still a bit confused about whey there isn't one
here let me find a proof for you
This is taken from Rudin, principles of mathematical analysis
Let A be the set of all positive rational p such that p^2<2 and let B consist of all positive rational p such that p^2>2. We shall show that A contains no largest number and B contains no smallest.
omg it's scrambling my chats. Let me just take a picture fo ryou.
okay i might be having a proof in my textbook too in later pages im still reading construction rational numbers.. but i want to see the proof as its really interesting xD
GL with real analysis.... I tried to get through it multiple times and it's just too dense
they have constructed another greater rational number \(\large q\) based on the given rational number \(\large p\)
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