If a ball is thrown directly upward with a velocity of 46 ft/s, its height (in feet) after t seconds is given by y = 46t − 16t2. What is the maximum height attained by the ball? (Round your answer to the nearest whole number.)

Question

confluxepic · Answer

$$\huge \color{blue}{Welcome~To~OpenStudy!!!}$$

anonymous · Answer

You have to find the vertex (highest point in the graph)

anonymous · Answer

the x-coordinate of the vertex is 

-b
----
2a

in the equation ax^2+bx+c=0
where 
a=-16
b=46
c-0

anonymous · Answer

After you find that x-value, then you plug it into -16t^2+46 and that will give you the max height

anonymous · Answer

for the $$\frac{ -b }{ 2a }$$  i got  $$\frac{ 23 }{ 16 }$$

anonymous · Answer

Alright, now you have to plug that into -16t^2+46t

anonymous · Answer

you have to plug in 23/16 for everywhere you see t

anonymous · Answer

yea, It should be 33.0625

anonymous · Answer

I must have done something wrong because my end answaer was 529.

anonymous · Answer

How did you get to 33.0625 from 529